Hall-Héroult Process (Aluminum Smelting)

2Al2O3 + 3C → 4Al + 3CO2

अवलोकन

Alumina (Al₂O₃) is dissolved in molten cryolite (Na₃AlF₆) at 960°C and electrolyzed using carbon anodes. Aluminum is deposited at the cathode and oxygen reacts with the carbon anode to form CO₂. Independently invented by Charles Hall and Paul Héroult in 1886, this process reduced aluminum from a precious metal to a commodity.

प्रतिभागी

भूमिका पदार्थ गुणांक अवस्था
अभिकारक Aluminum Oxide Al₂O₃ 2 (l)
अभिकारक Carbon C 3 (s)
उत्पाद Carbon Dioxide CO₂ 3 (g)
उत्पाद Aluminum Al 4 (l)

रोजमर्रा का उदाहरण

Every piece of aluminum foil, beverage can, and airplane wing was produced by the Hall-Héroult process.

औद्योगिक महत्व

Aluminum smelting produces 65 million tonnes annually and consumes about 3% of global electricity. Recycling uses only 5% of the energy.

गुण

प्रकार
Electrochemical
प्रतिवर्ती
नहीं
ऊर्जा
ऊष्माशोषी
ΔH
2168.0 kJ/mol
उत्प्रेरक
Cryolite (Na₃AlF₆) solvent

संबंधित अभिक्रियाएँ

Electrolysis of Water Electrolytic Production of Chlorate Electrorefining of Copper Alkaline Battery Discharge Anodizing of Aluminum Cathodic Protection (Zinc Sacrificial Anode) Chlor-Alkali Electrolysis Chrome Electroplating Nickel-Metal Hydride Battery Electrochemical CO₂ Reduction to CO

Frequently Asked Questions

What is the equation for Hall-Héroult Process (Aluminum Smelting)?
The balanced equation is: 2Al₂O₃ + 3C → 4Al + 3CO₂.
What type of reaction is Hall-Héroult Process (Aluminum Smelting)?
Hall-Héroult Process (Aluminum Smelting) is a electrochemical reaction.
Is Hall-Héroult Process (Aluminum Smelting) exothermic or endothermic?
Hall-Héroult Process (Aluminum Smelting) is endothermic (absorbs energy). The enthalpy change (ΔH) is 2168.0 kJ/mol.
What conditions are needed for Hall-Héroult Process (Aluminum Smelting)?
This reaction requires a catalyst (Cryolite (Na₃AlF₆) solvent).