Triple Alpha Process (Helium Burning)

34He → 12C + γ

अवलोकन

Three helium-4 nuclei fuse to form carbon-12 in stars through the triple-alpha process, which occurs above 100 million K. Two helium nuclei first form unstable beryllium-8, which immediately captures a third helium to form carbon-12 via the Hoyle state resonance. Fred Hoyle predicted this resonance to explain carbon abundance.

प्रतिभागी

भूमिका पदार्थ गुणांक अवस्था
अभिकारक Helium He 3 (g)
उत्पाद Carbon C 1 (s)

रोजमर्रा का उदाहरण

All the carbon in your body, in every living thing, and in diamonds was forged inside stars by this triple-alpha process.

औद्योगिक महत्व

Understanding stellar nucleosynthesis explains the cosmic abundance of elements and guides nuclear astrophysics research.

गुण

प्रकार
Nuclear
प्रतिवर्ती
नहीं
ऊर्जा
ऊष्माक्षेपी
ΔH
-730000000.0 kJ/mol

संबंधित अभिक्रियाएँ

Alpha Decay of Radium-226 Alpha Decay of Radon-222 Alpha Decay of Thorium-232 Neutron Capture by Uranium-238 Beta Decay of Iodine-131 Beta Decay of Strontium-90 Alpha Decay of Polonium-210 Americium-241 Alpha Decay Beta Decay of Cobalt-60 Electron Capture by Beryllium-7

Frequently Asked Questions

What is the equation for Triple Alpha Process (Helium Burning)?
The balanced equation is: 3⁴He → ¹²C + γ.
What type of reaction is Triple Alpha Process (Helium Burning)?
Triple Alpha Process (Helium Burning) is a nuclear reaction.
Is Triple Alpha Process (Helium Burning) exothermic or endothermic?
Triple Alpha Process (Helium Burning) is exothermic (releases energy). The enthalpy change (ΔH) is -730000000.0 kJ/mol.