Formation of Vanadium(V) Oxide
4V + 5O2 → 2V2O5
Overview
Vanadium metal reacts with oxygen to form vanadium(V) oxide (vanadium pentoxide). This orange-yellow compound is a powerful catalyst used in the Contact Process for sulfuric acid production. It exhibits catalytic properties due to its ability to cycle between oxidation states.
Participants
| Role | Substance | Coefficient | State |
|---|---|---|---|
| Reactant | Vanadium V | 4 | (s) |
| Reactant | Oxygen O | 5 | (g) |
| Product | Vanadium(V) Oxide V₂O₅ | 2 | (s) |
Everyday Example
Vanadium pentoxide is used in some specialized ceramics and glass to produce a yellow or amber color.
Industrial Importance
V2O5 is the primary catalyst in sulfuric acid manufacturing (Contact Process), making it indirectly responsible for producing the world's most-used chemical. Also used in vanadium redox flow batteries.
Properties
- Type
- Synthesis
- Reversible
- No
- Energy
- Exothermic
- ΔH
- -3102.0 kJ/mol
Related Reactions
Fischer-Tropsch Synthesis (General)
Formation of Aluminum Oxide
Formation of Ammonia (Haber Process)
Formation of Barium Oxide
Formation of Barium Sulfate
Formation of Beryllium Oxide
Formation of Cadmium Oxide
Formation of Calcium Carbonate from Oxides
Formation of Calcium Hydroxide
Formation of Calcium Oxide (Quicklime)
Frequently Asked Questions
What is the equation for Formation of Vanadium(V) Oxide?
The balanced equation is: 4V + 5O₂ → 2V₂O₅.
What type of reaction is Formation of Vanadium(V) Oxide?
Formation of Vanadium(V) Oxide is a synthesis reaction.
Is Formation of Vanadium(V) Oxide exothermic or endothermic?
Formation of Vanadium(V) Oxide is exothermic (releases energy). The enthalpy change (ΔH) is -3102.0 kJ/mol.