Copper Oxidation by Nitric Acid

3Cu + 8HNO3(dilute) → 3Cu(NO3)2 + 2NO + 4H2O

概要

Dilute nitric acid oxidizes copper to Cu²⁺ while the nitrate ion is reduced to nitric oxide (NO) gas. Unlike HCl or H₂SO₄(dilute), nitric acid can dissolve copper because the nitrate ion acts as the oxidizing agent. The solution turns blue from Cu(NO₃)₂ and the NO gas oxidizes in air to brown NO₂.

参加者

役割 物質 係数 状態
反応物 Copper Cu 3 (s)
反応物 Nitric Acid HNO₃ 8 (aq)
生成物 Water H₂O 4 (l)

日常の例

Chemistry students observe this reaction as a dramatic demonstration where copper dissolves in HNO₃ with brown fumes forming above the solution.

産業上の重要性

硝酸中での銅の溶解は、分析化学、プリント基板製造のための銅エッチング、そして金属精錬に使用されています。

Frequently Asked Questions

What is the equation for Copper Oxidation by Nitric Acid?
The balanced equation is: 3Cu + 8HNO₃(dilute) → 3Cu(NO₃)₂ + 2NO + 4H₂O.
What type of reaction is Copper Oxidation by Nitric Acid?
Copper Oxidation by Nitric Acid is a redox reaction.
Is Copper Oxidation by Nitric Acid exothermic or endothermic?
Copper Oxidation by Nitric Acid is exothermic (releases energy). The enthalpy change (ΔH) is -135.0 kJ/mol.