Ostwald Process NO Oxidation

4NH3 + 5O2 → 4NO + 6H2O

概要

Ammonia is catalytically oxidized to nitric oxide over a platinum-rhodium gauze catalyst at about 850 C in the Ostwald process. Nitrogen is oxidized from -3 in NH₃ to +2 in NO. The NO is further oxidized to NO₂ and absorbed in water to make nitric acid. This process links the Haber process to nitric acid production.

参加者

役割 物質 係数 状態
反応物 Ammonia NH₃ 4 (g)
反応物 Oxygen O 5 (g)
生成物 Water H₂O 6 (g)

日常の例

Nearly all explosives, from TNT to ammonium nitrate, begin with nitric acid produced by this catalytic oxidation of ammonia.

産業上の重要性

オストワルト法は世界の硝酸のほぼ全量を生産しており、肥料（硝酸アンモニウム）、爆薬、化学製品の製造に不可欠である。

特性

タイプ
Redox
可逆的
いいえ
エネルギー
発熱性
ΔH
-905.0 kJ/mol
触媒
Platinum-rhodium gauze

関連する反応

Iron(II) to Iron(III) Oxidation by Oxygen Bleaching with Sodium Hypochlorite Copper Reduction of Silver Ion Aqua Regia Dissolving Gold Cerium(IV) Reduction by Iron(II) Chlorine Oxidation of Bromide Copper Oxidation by Nitric Acid Hypochlorite Oxidation of Hydrogen Peroxide Hydrogen Peroxide as Oxidizing Agent (Acidic) Displacement of Hydrogen from Acid by Magnesium

Frequently Asked Questions

What is the equation for Ostwald Process NO Oxidation?
The balanced equation is: 4NH₃ + 5O₂ → 4NO + 6H₂O.
What type of reaction is Ostwald Process NO Oxidation?
Ostwald Process NO Oxidation is a redox reaction.
Is Ostwald Process NO Oxidation exothermic or endothermic?
Ostwald Process NO Oxidation is exothermic (releases energy). The enthalpy change (ΔH) is -905.0 kJ/mol.
What conditions are needed for Ostwald Process NO Oxidation?
This reaction requires a catalyst (Platinum-rhodium gauze).