마그네슘을 이용한 기체 화학양론
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Mg와 HCl의 반응으로 몰부피 계산하기
목표
알려진 질량의 마그네슘 리본을 과량의 염산과 반응시켜 상온 조건에서 수소 기체의 몰부피를 결정한다.
배경
When magnesium reacts with HCl, hydrogen gas is produced: Mg + 2HCl → MgCl₂ + H₂. By measuring the mass of Mg used and the volume of H₂ collected, the molar volume at room conditions can be calculated and compared with the theoretical value at STP (22.4 L/mol).
안전 경고
- HCl is corrosive
- Hydrogen is flammable — no flames
- Handle glassware carefully
필수 개인 보호 장비
재료
-
Magnesium ribbon (0.1 g)Accurately weighed
-
Hydrochloric acid (HCl) (30 mL)2M, excess
-
Distilled water (500 mL)
장비
실험 절차
Weigh a 3-4 cm strip of magnesium ribbon accurately. Record mass to 0.001 g.
Roll the Mg ribbon and secure it in a copper wire cage attached to a rubber stopper.
Fill the eudiometer tube with 2M HCl. Insert the stopper+Mg assembly, inverting the tube into the trough.
Allow the reaction to complete. All the Mg should dissolve, producing H₂ gas that collects at the top.
Equalize water levels inside and outside the tube. Read the gas volume at the meniscus.
Record room temperature and atmospheric pressure.
Correct for water vapor pressure. Calculate moles of H₂ from Mg mass. Determine molar volume.
예상 결과
0.1 g Mg = 0.00411 mol, producing 0.00411 mol H₂. At room conditions (~25°C, 1 atm), volume should be about 100 mL. Calculated molar volume at STP should be approximately 22.4 L/mol (±5%).
정리
Neutralize remaining HCl with NaHCO₃. Dispose down the drain. Rinse all equipment.
세부 정보
- 카테고리
- Gas Laws
- 난이도
- Intermediate (High School)
- 소요 시간
- 40 분
- 예상 비용
- $8.00
- 단계
- 7
- 재료
- 3